Slide17.JPG

Slide18.JPG
Slide19.JPG

Go Ad-free

Transcript

Example 9 Discuss the continuity of the function f defined by 𝑓 (π‘₯) = 1/π‘₯ , π‘₯ β‰  0. Given 𝑓 (π‘₯) = 1/π‘₯ At 𝒙 = 𝟎 𝑓 (0) = 1/0 = ∞ Hence, 𝑓(π‘₯) is not defined at 𝒙=𝟎 By definition, 𝑓 (π‘₯) = 1/π‘₯ , π‘₯ β‰  0. So, we check for continuity at all points except 0. Let c be any real number except 0. f is continuous at π‘₯ =𝑐 if , (π₯𝐒𝐦)┬(𝐱→𝒄) 𝒇(𝒙)=𝒇(𝒄) L.H.S L.H.S (π₯𝐒𝐦)┬(𝐱→𝒄) 𝒇(𝒙) = lim┬(x→𝑐) 1/π‘₯ Putting π‘₯ =𝑐 = 1/𝑐 R.H.S 𝒇(𝒄) =1/𝑐 " " Since, L.H.S = R.H.S ∴ Function is continuous at x = c (Except 0) Since, L.H.S = R.H.S ∴ Function is continuous at x = c (Except 0) Thus, we can write that f is continuous for all 𝒙 βˆˆπ‘βˆ’{𝟎}

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo