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Last updated at April 16, 2024 by Teachoo
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Example 1 Check the continuity of the function f given by f (x) = 2x + 3 at x = 1. π(π₯) is continuous at π₯=1 if limβ¬(xβ1) π(π₯) = π(1) (π₯π’π¦)β¬(π±βπ) π(π) "= " limβ¬(xβ1) " "(2π₯+3) = 2 Γ 1 + 3 = 2 + 3 = 5 (π₯π’π¦)β¬(π±βπ) π(π) "= " limβ¬(xβ1) " "(2π₯+3) = 2 Γ 1 + 3 = 2 + 3 = 5 π(π) = 2 Γ 1 + 3 = 2 + 3 = 5 π(π) = 2 Γ 1 + 3 = 2 + 3 = 5 Since, L.H.S = R.H.S β΄ Function is continuous.