Slide1.JPG

Slide2.JPG

Go Ad-free

Transcript

Misc 1 Differentiate w.r.t. x the function, (3𝑥2 – 9𝑥 + 5)^9Let 𝑦=(3𝑥2 – 9𝑥 + 5)^9 Differentiating 𝑤.𝑟.𝑡.𝑥. 𝑑𝑦/𝑑𝑥 = (𝑑(3𝑥2 – 9𝑥 + 5)^9)/𝑑𝑥 = 9(3𝑥2 – 9𝑥 + 5)^(9 −1) . 𝑑(3𝑥2 – 9𝑥 + 5)/𝑑𝑥 = 9(3𝑥2 – 9𝑥 + 5)^8 . (𝑑(3𝑥2)/𝑑𝑥 − 𝑑(9𝑥)/𝑑𝑥 − 𝑑(5)/𝑑𝑥) = 9(3𝑥2 – 9𝑥 + 5)^8 . (6𝑥−9+0) = 9(3𝑥2 – 9𝑥 + 5)^8 . (6𝑥−9) = 9(3𝑥2 – 9𝑥 + 5)^8 . 3(2𝑥−3) = 𝟐𝟕(𝟑𝒙𝟐 – 𝟗𝒙 + 𝟓)^𝟖 (𝟐𝒙−𝟑)

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo