Finding derivative of a function by chain rule
Finding derivative of a function by chain rule
Last updated at Dec. 16, 2024 by Teachoo
Ex 5.2, 1 Differentiate the functions with respect to π₯ sinβ‘(π₯2 + 5) y = sin (x2 + 5) We need to find derivative of π¦, π€.π.π‘.π₯ (ππ¦ )/ππ₯ = (π(sinβ‘(π₯2 + 5)))/ππ₯ = cos (π₯2 + 5) Γ π(π₯2 + 5)/ππ₯ = cos (π₯2 + 5) Γ ((π(π₯2))/ππ₯+ (π(5))/ππ₯) = cos (π₯2 + 5) Γ (γ2π₯γ^(2β1) + 0) = cos (π₯2 + 5) Γ 2π₯ = ππ πππβ‘γ (ππ + π)γ