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Question 1 - Equation of line - given 2 points - Chapter 11 Class 12 Three Dimensional Geometry
Last updated at April 16, 2024 by Teachoo
Equation of line - given 2 points
Chapter 11 Class 12 Three Dimensional Geometry
Concept wise
- Direction cosines and ratios
- Equation of line - given point and //vector
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Equation of line - given 2 points
- Angle between two lines - Vector
- Angle between two lines - Cartisian
- Angle between two lines - Direction ratios or cosines
- Shortest distance between two skew lines
- Shortest distance between two parallel lines
- Equation of plane - In Normal Form
- Equation of plane - Prependicular to Vector & Passing Through Point
- Equation of plane - Passing Through 3 Non Collinear Points
- Equation of plane - Intercept Form
- Equation of plane - Passing Through Intersection Of Planes
- Coplanarity of 2 lines
- Angle between two planes
- Distance of point from plane
- Angle between Line and Plane
- Equation of line under planes condition
- Point with Lines and Planes
Transcript
Question 1 Find the vector equation for the line passing through the points ( 1, 0, 2) and (3, 4, 6). Vector equation Vector equation of a line passing though two points with position vectors and is = + ( ) Given, Let two points be A ( 1, 0, 2) & B(3, 4, 6) So, = ( + 0 + 2 ) + 3 +4 +6 ( + 0 + 2 ) = + 0 + 2 + 3 + 4 + 6 + 0 2 = + 0 + 2 + 3 + 1 + 4 0 + (6 2) = + 0 + 2 + 4 + 4 + 4 = + 2 + + + Therefore, the vector equation is + 2 + 4 + 4 + 4
