Find volume of parallelepiped whose edges are a = 2i - 3j + 4k, b = i - Supplementary examples and questions from CBSE

part 2 - Supplementary Example 2 - Supplementary examples and questions from CBSE - Serial order wise - Chapter 10 Class 12 Vector Algebra

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Supplementary Example 2 Find the volume of the parallelepiped whose edges are π‘Ž βƒ— = 2𝑖 Μ‚ βˆ’ 3𝑗 Μ‚ + 4π‘˜ Μ‚, 𝑏 βƒ— = 𝑖 Μ‚ + 2𝑗 Μ‚ βˆ’ π‘˜ Μ‚ and 𝑐 βƒ— = 2𝑖 Μ‚ βˆ’ 𝑗 Μ‚ + 2π‘˜ Μ‚ Given, π‘Ž βƒ— = 2𝑖 Μ‚ βˆ’ 3𝑗 Μ‚ + 4π‘˜ Μ‚ , 𝑏 βƒ— = 𝑖 Μ‚ + 2𝑗 Μ‚ – π‘˜ Μ‚ , 𝑐 βƒ— = 2𝑖 Μ‚ – 𝑗 Μ‚ + 2π‘˜ Μ‚ Volume of parallelepiped = [𝒂 βƒ—" " 𝒃 βƒ—" " 𝒄 βƒ— ] = |β– 8(2&βˆ’3&4@1&2&βˆ’1@2&βˆ’1&2)| = 2[(2Γ—2)βˆ’(βˆ’1Γ—βˆ’1) ] βˆ’ (βˆ’3) [(1Γ—2)βˆ’(2Γ—βˆ’1) ] + 4[(1Γ—βˆ’1)βˆ’(2Γ—2)] = 2 [4βˆ’1]+3(2+2)+4[βˆ’1βˆ’4] = 2(3) + 3 (4) + 4(–5) = 6 + 12 – 20 = –2 Since volume is always positive Volume of parallelepiped = 2 cubic units

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo