Chapter 10 Class 12 Vector Algebra
Ex 10.2, 9
Ex 10.2, 10 Important
Ex 10.2, 13 Important
Ex 10.2, 17 Important
Example 14 Important You are here
Example 16 Important
Example 21 Important
Ex 10.3, 2
Ex 10.3, 3 Important
Ex 10.3, 10 Important
Ex 10.3, 13 Important
Ex 10.3, 16 Important
Example 23 Important
Example 24
Example 25 Important
Ex 10.4, 2 Important
Ex 10.4, 5 Important
Ex 10.4, 9 Important
Ex 10.4, 10
Ex 10.4, 11 (MCQ) Important
Example 28 Important
Example 29 Important
Example 30 Important
Misc 6
Misc 12 Important
Misc 13
Misc 15 Important
Misc 19 (MCQ) Important
Chapter 10 Class 12 Vector Algebra
Last updated at April 16, 2024 by Teachoo
Example 14 Find angle βΞΈβ between the vectors π β = π Μ + π Μ β π Μ and π β = π Μ β π Μ + π Μ. Given π β = π Μ + π Μ β π Μ π β = π Μ β π Μ + π Μ We know that π β . π β = "|" π β"|" "|" π β"|" cos ΞΈ where ΞΈ is the angle between π β and π β Finding |π β |, |π β | and π β . π β Magnitude of π β = β(12+1^2+(β1)2) |π β | = β(1+1+1) = βπ Magnitude of π β = β(12+(β1)2+12) |π β | = β(1+1+1) = βπ Finding π β . π β π β . π β = (1π Μ + 1π Μ β 1π Μ). (1π Μ β 1π Μ + 1π Μ) = 1.1 + 1.(β1) + (β1)1 = 1 β 1 β 1 = β1 Now, π β . π β = "|" π β"|" "|" π β"|" cos ΞΈ Putting values β1 = β3 Γ β3 Γ cos ΞΈ β1 = 3 cos ΞΈ cos ΞΈ = (β1)/3 ΞΈ = cosβ1 ((βπ)/π) Therefore, the angle between π β and π β is cos-1((β1)/3)