Example 9 - Chapter 10 Class 12 Vector Algebra
Last updated at Dec. 16, 2024 by Teachoo
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Example 9 Write the direction ratioβs of the vector π β = π Μ + π Μ β 2π Μ and hence calculate its direction cosines. Given π β = π Μ + π Μ β 2π Μ = 1π Μ + 1π Μ β 2π Μ Directions ratios are π = 1 , b = 1 , c = β2 Magnitude of π β = β(1^2+1^2+(β2)^2 ) |π| = β(1+1+4) = βπ The directions cosines of π β are (π/|π β | ,π/|π β | ,π/|π β | ) = (π/βπ,π/βπ,(βπ)/βπ)
