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Example 8 - Chapter 10 Class 12 Vector Algebra
Last updated at April 16, 2024 by Teachoo
Addition(resultant) of vectors
Chapter 10 Class 12 Vector Algebra
Concept wise
- Scalar or vector
- Graphical displacement
- Type of vector
- Multiplication of a vector by a scalar
- Equal vectors
- Unit vector
- Direction cosines and ratios
-
Addition(resultant) of vectors
- Joining two points
- Section formula
- Right Angled triangle
- Collinearity Of two vectors
- Collinearity of 3 points or 3 position vectors
- Scalar product - Defination
- Scalar product - Projection
- Scalar product - Solving
- Vector product - Defination
- Vector product - Area
- Vector product - Solving
Transcript
Example 8 Find the unit vector in the direction of the sum of the vectors, 𝑎 ⃗ = 2𝑖 ̂ + 2 𝑗 ̂ – 5𝑘 ̂ and 𝑏 ⃗ = 2𝑖 ̂ + 𝑗 ̂ + 3𝑘 ̂ Given 𝒂 ⃗ = 2𝑖 ̂ + 2𝑗 ̂ – 5𝑘 ̂ 𝒃 ⃗ = 2𝑖 ̂ + 1𝑗 ̂ + 3𝑘 ̂ Let 𝒄 ⃗ = (𝒂 ⃗ + 𝒃 ⃗) = (2 + 2) 𝑖 ̂ + (2 + 1) 𝑗 ̂ + (–5 + 3) 𝑘 ̂ = 4𝑖 ̂ + 3𝑗 ̂ – 2𝑘 ̂ ∴ 𝒄 ⃗ = 4𝒊 ̂ + 3𝒋 ̂ – 2𝒌 ̂ Magnitude of 𝑐 ⃗ = √(42+32+(−2)2) |𝒄 ⃗ | = √(16+9+4) = √𝟐𝟗 Unit vector in direction of 𝑐 ⃗ = 𝟏/|𝒄 ⃗ | 𝒄 ⃗ 𝑐 ̂ = 1/√29 ["4" 𝑖 ̂" + 3" 𝑗 ̂" − 2" 𝑘 ̂ ] 𝑐 ̂ = 4/√29 𝑖 ̂" " + 3/√29 𝑗 ̂" "– 2/√29 𝑘 ̂" " Thus, Required unit vector = 𝟒/√𝟐𝟗 𝒊 ̂" " + 𝟑/√𝟐𝟗 𝒋 ̂" "– 𝟐/√𝟐𝟗 𝒌 ̂
