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Example 7 - Chapter 10 Class 12 Vector Algebra
Last updated at Dec. 16, 2024 by Teachoo
Chapter 10 Class 12 Vector Algebra
Concept wise
- Scalar or vector
- Graphical displacement
- Type of vector
- Multiplication of a vector by a scalar
- Equal vectors
-
Unit vector
- Direction cosines and ratios
- Addition(resultant) of vectors
- Joining two points
- Section formula
- Right Angled triangle
- Collinearity Of two vectors
- Collinearity of 3 points or 3 position vectors
- Scalar product - Defination
- Scalar product - Projection
- Scalar product - Solving
- Vector product - Defination
- Vector product - Area
- Vector product - Solving
Transcript
Example 7 Find a vector in the direction of vector 𝑎 ⃗ = 𝑖 ̂ − 2𝑗 ̂ that has magnitude 7 units. Given 𝒂 ⃗ = 𝑖 ̂ – 2𝑗 ̂ = 1𝑖 ̂ – 2𝑗 ̂ + 0𝑘 ̂ Magnitude of 𝒂 ⃗ = √(12+(−2)2+02) |𝒂 ⃗ | = √(1+4+0) = √𝟓 Unit vector in direction of 𝑎 ⃗ = 𝟏/(𝑴𝒂𝒈𝒏𝒊𝒕𝒖𝒅𝒆 𝒐𝒇 𝒂 ⃗ ) × 𝒂 ⃗ 𝑎 ̂ = 1/√5 ["1" 𝑖 ̂" + " 2𝑗 ̂" + " 0𝑘 ̂ ] 𝑎 ̂ = 1/√5 𝑖 ̂ − 2/√5 𝑗 ̂ Thus, Vector having a magnitude 1 = 1/√5 𝑖 ̂ − 2/√5 𝑗 ̂ Vector having a magnitude 7 = 7[1/√5 " " 𝑖 ̂" − " 2/√5 " " 𝑗 ̂" " ] = 7/√5 " " 𝑖 ̂" − " 14/√5 " " 𝑗 ̂ Thus, required vector is 𝟕/√𝟓 " " 𝒊 ̂" − " 𝟏𝟒/√𝟓 " " 𝒋 ̂
