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Misc 1 (i) - Chapter 8 Class 12 Application of Integrals
Last updated at Dec. 16, 2024 by Teachoo
Area bounded by curve and horizontal or vertical line
Chapter 8 Class 12 Application of Integrals
Concept wise
- Area under curve
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Area bounded by curve and horizontal or vertical line
- Area between curve and line
- Area between curve and curve
Transcript
Misc 1 Find the area under the given curves and given lines: (i) 𝑦 = 𝑥2, 𝑥 = 1, 𝑥 = 2 and 𝑥-axisArea required = Area ABCD = ∫_𝟏^𝟐▒〖𝒚 𝒅𝒙〗 y → Equation of parabola 𝑦=𝑥^2 Thus, Area required = ∫_1^2▒〖𝑦 𝑑𝑥〗 =∫_𝟏^𝟐▒〖𝒙^𝟐 𝒅𝒙〗 =[𝑥^3/3]_1^2 =1/3 [2^3−1^3 ] = 1/3 [8−1] =𝟕/𝟑 square units
