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Question 6 (MCQ) - Area between curve and line - Chapter 8 Class 12 Application of Integrals
Last updated at July 20, 2026 by Teachoo
Area between curve and line
Chapter 8 Class 12 Application of Integrals
Concept wise
- Area under curve
- Area bounded by curve and horizontal or vertical line
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Area between curve and line
- Area between curve and curve
Transcript
Ex 8.2 , 6 Smaller area enclosed by the circle š„2+š¦2 =4 and the line š„+š¦=2 is (A) 2 (Ļ ā 2) (B) Ļ ā 2 (C) 2Ļ ā 1 (D) 2 (Ļ + 2) Step 1: Drawing figure Circle is š„2+š¦2 =4 (š„ā0)2+(š¦ā0)2 = 2ļ·®2ļ·Æ So, Center = (0, 0) & Radius = 2 Also, š„+š¦=2 passes through (0, 2) & (2, 0) Hence, intersecting points A = (2, 0) & B = (0, 2) Thus, Area required = Area OACB ā AREA OAB = š ā 2 Thus, Option (B) is correct.
