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Last updated at April 16, 2024 by Teachoo
Example 4 Evaluate ∆ = |■8(0&sin𝛼&−cos𝛼@−sin𝛼&0&sinβ@cos𝛼&−sinβ&0)| ∆ =|■8(0&sin𝛼&−cos𝛼@−sin𝛼&0&sinβ@cos𝛼&−sinβ&0)| = 0(0 + sin2 β) – sin 𝛼 (0 – cos α sin β) – cos 𝛼 (sin 𝛼 sin β – 0) = 0 – sin 𝛼 (–cos 𝛼 sin β ) – cos 𝛼 (sin 𝛼 sin β) = sin 𝛼 cos 𝛼 sin β – cos 𝛼 sin 𝛼 sin β = sin 𝛼 cos 𝛼 sin β – sin 𝛼 cos 𝛼 sin β = 0