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Ex 4.5, 6 - Chapter 4 Class 12 Determinants
Last updated at April 16, 2024 by Teachoo
Checking consistency of equations
Chapter 4 Class 12 Determinants
Concept wise
- Finding determinant of a 2x2 matrix
- Evalute determinant of a 3x3 matrix
- Area of triangle
- Equation of line using determinant
- Finding Minors and cofactors
- Evaluating determinant using minor and co-factor
- Find adjoint of a matrix
- Finding Inverse of a matrix
- Inverse of two matrices and verifying properties
- Finding inverse when Equation of matrice given
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Checking consistency of equations
- Find solution of equations- Equations given
- Find solution of equations- Statement given
- Verifying properties of a determinant
- Two rows or columns same
- Whole row/column zero
- Whole row/column one
- Making whole row/column one and simplifying
- Proving Determinant 1 = Determinant 2
- Solving by simplifying det.
- Using Property 5 (Determinant as sum of two or more determinants)
Transcript
Ex 4.5, 6 Examine the consistency of the system of equations. 5x − y + 4z = 5 2x + 3y + 5z = 2 5x − 2y + 6z = −1 The system of equations is 5x − y + 4z = 5 2x + 3y + 5z = 2 5x − 2y + 6z = −1 Writing equation as AX = B [■8(5&−1&4@2&3&5@5&−2&6)] [■8(𝑥@𝑦@𝑧)] = [■8(5@2@−1)] Hence A = [■8(5&−1&4@2&3&5@5&−2&6)], X = [■8(𝑥@𝑦@𝑧)] & B = [■8(5@2@−1)] Calculating |A| |A| = |■8(5&−1&4@2&3&5@5&−2&6)| = 5 |■8(3&5@−2&6)| – 1 (–1) |■8(2&5@5&6)| + 4|■8(2&3@5&−2)| = 5 (18 + 10) + 1(12 – 25) + 4(–4 – 15) = 5 (28) + 1 (–13) + 4(–19) = 140 – 13 – 76 = 51 ≠ 0 Since |A| ≠ 0 The given system of equation is consistent
