Ex 4.1, 7 (i) - Chapter 4 Class 12 Determinants (Important Question)

Last updated at Dec. 16, 2024 by

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Ex 4.1, 7 Find values of x, if (i) |■8(2&4@5&1)| = |■8(2x&4@6&x)| Now |■8(2&4@5&1)| = |■8(2x&4@6&x)| Putting values −18 = 2x2 – 24 2x2 – 24 = −18 2x2 = −18 + 24 2x2 = 6 Calculating |■8(2&4@5&1)| = 2(1) – 5(4) = 2 – 20 = – 18 Calculating |■8(2x&4@6&x)| = 2x(x) – 6 × 4 = 2x2 – 24 x2 = 6/2 x2 = 3 x = ± √𝟑 Hence, value of x is ± √3

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo