Example 8 - Chapter 3 Class 12 Matrices
Last updated at Dec. 16, 2024 by Teachoo
Examples
Example 2
Example 3 Important
Example 4
Example 5 Important
Example 6
Example 7
Example 8 You are here
Example 9
Example 10
Example 11 Important
Example 12
Example 13 Important
Example 14
Example 15
Example 16 Important
Example 17
Example 18 Important
Example 19
Example 20 Important
Example 21
Example 22 Important
Example 23 Important
Example 24 Important
Example 25
Question 1
Question 2 Important
Question 3 Important
Last updated at Dec. 16, 2024 by Teachoo
Example 8 If A = [■8(8&0@4&−2@3&6)] and B = [■8(2&−2@4&2@−5&1)] then find the matrix X, such that 2A + 3X = 5B. Given that 2A + 3X = 5B Putting values 2 [■8(𝟖& 𝟎@𝟒&−𝟐@𝟑& 𝟔)] + 3X = 5 [■8( 𝟐&−𝟐@ 𝟒& 𝟐@−𝟓& 𝟏)] [■8(8 × 2 & 0 × 2@4 × 2&−2 × 2@3 × 2& 6 × 2)] + 3X = [■8( 2 × 5 &−2 × 5@ 4 × 5& 2 × 5@−5 × 5& 1 × 5)] [■8(16& 0@8& −4@6& 12)] + 3X = [■8( 10&−10@ 20& 10@−25& 5)] 3X = [■8(𝟏𝟎&−𝟏𝟎@𝟐𝟎&𝟏𝟎@−𝟐𝟓&𝟓)] – [■8(𝟏𝟔& 𝟎@𝟖&−𝟒@𝟔&𝟏𝟐)] 3X = [■8( 10−16&−10−0@ 20−8&10−(−4)@−25−6& 5−12)] 3X = [■8( −𝟔&−𝟏𝟎@ 𝟏𝟐& 𝟏𝟒@−𝟑𝟏& −𝟕)] X = 1/3 [■8( −6&−10@ 12& 14@−31& −7)] X = [■8((−6)/3&(−10)/3@(−12)/3&14/3@(−31)/3&(−7)/3)] X = [■8(−𝟐&(−𝟏𝟎)/𝟑@𝟒&𝟏𝟒/𝟑@(−𝟑𝟏)/𝟑&(−𝟕)/𝟑)] Hence, X = [■8(−2&(−10)/3@4&14/3@(−31)/3&(−7)/3)]