Transpose of a matrix
Last updated at April 16, 2024 by Teachoo
Ex 3.3, 4 If A’ = [■8(−2&3@1&2)] and B = [■8(−1&0@1&2)] , then find (A + 2B)’ We need to find (A + 2B)’ Finding A A’ = [■8(−2&3@1&2)] A = (A’)’ = [■8(−𝟐&𝟏@𝟑&𝟐)] Also, B = [■8(−1&0@1&2)] 2B = 2 [■8(−1&0@1&2)] = [■8(2(−1)&2(0)@2(1)&2(2))] = [■8(−𝟐&𝟎@𝟐&𝟒)] Now A + 2B = [■8(−2&1@3&2)] + [■8(−2&0@2&4)] = [■8(2+(−2)&1+0@3+2&2+4)] = [■8(𝟎&𝟏@𝟓&𝟔)] ∴ (A + 2B) = [■8(−4&1@5&6)] So, (A + 2B)’ = [■8(−𝟒&𝟓@𝟏&𝟔)]