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Ex 3.2, 12 Given 3[■8(x&y@z&w)] = [■8(x&6@−1&2w)] + [■8(4&x+y@z+w&3)] find the values of x, y, z and w. 3[■8(x&y@z&w)] = [■8(x&6@−1&2w)] + [■8(4&x+y@z+w&3)] [■8(3x&3y@3z&3w)] = [■8(x+4&6+x+y@1−z+w&2w+3)] Since matrices are equal. Corresponding elements are equal 3x = x + 4 3y = 6 + x + y 3z = 1 – z + w 3w = 2w + 3 Solving equation (1) 3x = x + 4 3x – x = 4 2x = 4 x = 4/2 x = 2 Solving equation (2) 3y = 6 + x + y 3y – y = 6 + x 2y = 6 + x Putting x = 2 2y = 6 + 2 2y = 8 y = 8/2 y = 4 Solving equation (4) 3w = 2w + 3 3w – 2w = 3 w = 3 Solving equation (3) 3z = – 1 + z + w 3z – z = – 1 + w 2z = – 1 + w Putting w = 3 2z = – 1 + 3 2z = 2 z = 2/2 z = 1 Hence, x = 2, y = 4 , w = 3 & z = 1

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo