Finding principal value
Example 1 Important
Ex 2.1, 1
Ex 2.1, 3
Ex 2.1, 10 Important
Ex 2.1, 2
Ex 2.1, 5 Important
Ex 2.1, 9
Ex 2.1, 7 Important
Ex 2.1, 4 Important You are here
Ex 2.1, 6
Ex 2.1, 8 Important
Example 2
Ex 2.2, 10
Example 6 Important
Ex 2.2, 8
Ex 2.2, 11
Misc 2 Important
Ex 2.2, 13 (MCQ) Important
Misc 1
Ex 2.2, 14 (MCQ) Important
Ex 2.2, 15 (MCQ)
Ex 2.1, 12 Important
Ex 2.1, 14 (MCQ) Important
Ex 2.1, 11 Important
Last updated at Dec. 16, 2024 by Teachoo
Ex 2.1, 4 (Method 1) Find the principal value of tan−1 (−√3) Let y = tan−1 (−√3) y = − tan−1 (√3) y = − 𝝅/𝟑 Since Range of tan−1 is ((−π)/2 "," π/2) Hence, Principal Value is (−𝝅)/𝟑 We know that tan−1 (−x) = − tan −1 x Since tan 𝜋/3 = √3 𝜋/3 = tan−1 (√3) Ex 2.1, 4 (Method 2) Find the principal value of tan−1 (−√3) Let y = tan−1 (−√3) tan y = −√3 tan y = tan ((−𝝅)/𝟑) Since Range of tan−1 is ((−π)/2 "," π/2) Hence, Principal Value is (−𝝅)/𝟑 Rough We know that tan 60° = √3 θ = 60° = 60° × 𝜋/180 = 𝜋/3 Since −√3 is negative Principal value is −θ i.e. (−𝜋)/3