Ex 14.2, 14 - Chapter 14 Class 11 Probability

Last updated at Dec. 16, 2024 by

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Ex 14.2, 14 Given P(A) = 3/5 and P(B) = 1/5. Find P(A or B), if A and B are mutually exclusive events. P(A) = 3/5 , P(B) = 1/5 Since A and B are mutually excusive So, P(A ∩ B) = 0 Now, P(A or B) = P(A ∪ B) We know that P(A ∪ B) = P(A) + P(B) – P(A ∩ B) Putting values P(A ∪ B) = 3/5 + 1/5 – 0 = (3 + 1)/5 = 4/5 Hence, P(A ∪ B) = 𝟒/𝟓

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo