Example 3 - Chapter 11 Class 11 - Intro to Three Dimensional Geometry

Last updated at Dec. 16, 2024 by

Slide3.JPG

Slide4.JPG

Go Ad-free

Transcript

Example 3 Find the distance between the points P(1, –3, 4) and Q (– 4, 1, 2). Given P (1, – 3, 4) and Q (– 4, 1, 2) Distance PQ = √((𝑥2−𝑥1)2+(𝑦2−𝑦1)2+(𝑧2 −𝑧1)2) Here, x1 = 1, y1 = – 3, z1 = 4 x2 = – 4, y2 = 1, z2 = 2 PQ = √((−4−1)2+(1−(−3))2+(2−4)2) = √((−5)2+(1+3)2+(−2)2) = √45 = √(3×3×5) = 3 √𝟓 units

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo