Example 2 - Chapter 11 Class 11 - Intro to Three Dimensional Geometry

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Example 2 Find the octant in which the points (–3, 1, 2) and (–3, 1, – 2) lie. (−3, 1, 2) Here x is negative, y is positive and z is positive So it lies in II octant. (ii) (−3, 1, −2) Here x is negative, y is positive and z is negative. So it lies in VI octant.

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo