Ex 10.4, 6 - Chapter 10 Class 11 Conic Sections
Last updated at April 19, 2024 by Teachoo
Hyperbola
Ex 10.4, 4
Ex 10.4, 2
Ex 10.4, 3 Important
Ex 10.4, 6 You are here
Ex 10.4, 5 Important
Example 14 (i)
Ex 10.4, 7 Important
Example 15
Ex 10.4, 8
Ex 10.4, 9 Important
Ex 10.4, 10
Ex 10.4, 11 Important
Ex 10.4, 12 Important
Ex 10.4, 13
Example 16 Important
Ex 10.4, 14 Important
Ex 10.4, 15 Important
Last updated at April 19, 2024 by Teachoo
Ex 10.4, 6 Find the coordinates of the foci and the vertices, the eccentricity, and the length of the latus rectum of the hyperbola 49y2 16x2 = 784 49y2 16x2 = 784 Dividing whole equation by 784 49 784 y2 16 784 x2 = 784 784 2 16 2 49 = 1 2 42 2 72 = 1 So our equation is of the form 2 2 2 2 = 1 Axis of hyperbola is y-axis Comparing (1) and (2) a2 = 42 a = 4 b2 = 72 b = 7 Also, c2 = a2 + b2 c2 = 72 + 42 c2 = 49 + 16 c2 = 65 c = Coordinates of focus is (0, c) = (0, 65 ) So, foci are (0, 65 ) & (0, 65 ) Coordinates of vertices = (0, a) = (0, 4) So, co-ordinates of vertices are (0, 4) & (0, 4) Eccentricity is e = = 65 4 Latus rectum = 2 2 = 2 7 2 4 = 2 49 4 = 49 2