Ex 10.4, 4 - Chapter 10 Class 11 Conic Sections
Last updated at April 19, 2024 by Teachoo
Hyperbola
Ex 10.4, 4 You are here
Ex 10.4, 2
Ex 10.4, 3 Important
Ex 10.4, 6
Ex 10.4, 5 Important
Example 14 (i)
Ex 10.4, 7 Important
Example 15
Ex 10.4, 8
Ex 10.4, 9 Important
Ex 10.4, 10
Ex 10.4, 11 Important
Ex 10.4, 12 Important
Ex 10.4, 13
Example 16 Important
Ex 10.4, 14 Important
Ex 10.4, 15 Important
Last updated at April 19, 2024 by Teachoo
Ex 10.4, 4 Find the coordinates of the foci and the vertices, the eccentricity, and the length of the latus rectum of the hyperbola 16x2 9y2 = 576 The given equation is 16x2 9y2 = 576. Dividing whole equation by 576 16 2 576 9 2 576 = 576 576 2 36 2 64 = 1 The above equation hyperbola is of the form 2 2 2 2 = 1 Axis of hyperbola is x axis Comparing (1) & (2) a2 = 36 a = 6 & b2 = 64 b = 8 Also, c2 = a2 + b2 c2 = 36 + 64 c2 = 100 c = 10 Co-ordinates of foci = ( c, 0) = ( 10, 0) So co-ordinate of foci are (10, 0) & ( 10, 0) Vertices = ( a, 0) = ( 6, 0) So, co-ordinates vertices are (6, 0) & ( 6, 0) Eccentricity e = = 10 6 = 5 3 Latus rectum = 2 2 = 2 64 6 = 64 3