Ex 10.2, 9 - Chapter 10 Class 11 Conic Sections

Last updated at April 17, 2024 by

Slide23.JPG

Slide24.JPG

Go Ad-free

Transcript

Ex 10.2, 9 Find the equation of the parabola that satisfies the following conditions: Vertex (0, 0); focus (3, 0) Since focus lies on y-axis Hence equation is either y2 = 4ax & y2 = 4ax Now focus has a negative y co-ordinate So, we have to use equation y2 = 4ax Coordinate of focus = (a, 0) (a, 0) = (3, 0) a = 3 Equation of parabola is y2 = 4ax y2 = 4(3)x y2 = 12x

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo