Ex 10.2, 9 - Chapter 10 Class 11 Conic Sections

Last updated at July 20, 2026 by

Ex 10.2, 9 - Find equation of parabola: Vertex (0, 0) focus (3,0) - Ex 10.2

part 2 - Ex 10.2, 9 - Ex 10.2 - Serial order wise - Chapter 10 Class 11 Conic Sections

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Ex 10.2, 9 Find the equation of the parabola that satisfies the following conditions: Vertex (0, 0); focus (3, 0) Since focus lies on y-axis Hence equation is either y2 = 4ax & y2 = 4ax Now focus has a negative y co-ordinate So, we have to use equation y2 = 4ax Coordinate of focus = (a, 0) (a, 0) = (3, 0) a = 3 Equation of parabola is y2 = 4ax y2 = 4(3)x y2 = 12x

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