Ex 10.2, 8 - Chapter 10 Class 11 Conic Sections

Last updated at April 17, 2024 by

Slide21.JPG

Slide22.JPG

Go Ad-free

Transcript

Ex 10.2, 8 Find the equation of the parabola that satisfies the following conditions: Focus (0, –3); directrix y = 3 Since focus lies on y-axis Hence equation is either x2 = 4ay & x2 = −4ay Now focus has a negative y co-ordinate So, we have to use equation x2 = −4ay Coordinate of focus = (0, −a) (0, −a) = (0, −3) −a = −3 a = 3 Equation of parabola is x2 = −4ay x2 = −4(3)y x2 = −12y

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo