Ex 10.1, 2 - Chapter 10 Class 11 Conic Sections

Last updated at Dec. 16, 2024 by

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Ex 10.1, 2 Find the equation of the circle with centre ( 2, 3) and radius 4 We know that equation of a circle is (x h)2 + (y k)2 = r2 Where (h, k) is the centre & r is the radius Here Centre (h, k) = ( 2, 3) So h = 2 & k = 3 & radius (r) = 4. Putting values in (1) (x ( 2))2 + (y 3)2 = (4)2 (x + 2)2 + (y 3)2 = 16 (x2 + 22 + 4x) + (y2 + 32 6y) = 16 x2 + 4 + 4x + y2 + 9 6y = 16 x2 + y2 + 4x 6y + 4 + 9 = 16 x2 + y2 + 4x 6y + 13 16 = 0 x2 + y2 + 4x 6y 3 = 0

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo