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Question 5 - Slope-Intercept form - Chapter 9 Class 11 Straight Lines
Last updated at Dec. 16, 2024 by Teachoo
Chapter 9 Class 11 Straight Lines
Concept wise
- Cordinate geometry questions
- Slope - Finding slope
- Slope - Prependicularity
- Angle between two lines by Slope
- Collinearity of 3 points by sliope
- Point Slope form
-
Slope-Intercept form
- Intercept form
- Normal form
- Given Statement
- Two lines // or/and prependicular
- Angle between two lines
- Distance - Between two parallel lines
- Distance of a point from a line
- Distance of a point from a line along a line
- Other Type of questions - Area of Triangle formed
- Other Type of questions - 3 lines Concurrent
- Other Type of questions - Image
- Other Type of questions - Mix
Transcript
Question 5 Equation of a line is 3x – 4y + 10 = 0. Find its (i) slope 3x – 4y + 10 = 0 −4y = −3x − 10 −4y = − (3x + 10) 4y = 3x + 10 y = (3𝑥 + 10)/4 y = 3/4 x + 10/4 y = 3/4x + 5/2 The above equation is of the form y = mx + c We convert it to y = mx + c where m is the slope & c is the y-intercept Here, m = 3/4 & c = 5/2 Hence, slope m = 𝟑/𝟒 & y-intercept = 5/2 Question 5 Equation of a line is 3x – 4y + 10 = 0. Find its (ii) x and y-intercepts. 3x – 4y + 10 = 0 3x − 4y = − 10 Dividing both sides by − 10 (3𝑥 − 4𝑦)/( −10) = ( −10)/( −10) 3𝑥/( −10) − 4𝑦/( −10) = 1 3𝑥/( −10) + 4𝑦/( 10) = 1 𝑥/(( −10)/3) + 𝑦/(10/4) = 1 𝑥/((−10)/3) + 𝑦/(5/2) = 1 The above equation of the form 𝑥/𝑎 + 𝑦/(𝑏 ) = 1 Hence, a = x-intercept = (−𝟏𝟎)/𝟑 & b = y-intercept = 𝟓/𝟐
