Question 3 - Examples - Chapter 9 Class 11 Straight Lines
Last updated at April 16, 2024 by Teachoo
Examples
Example 1 (b)
Example 1 (c) Important
Example 1 (d)
Example 2 Important
Example 3 Important
Example 4 Important
Example 5
Example 6
Example 7 (i)
Example 7 (ii) Important
Example 8
Example 9 Important
Example 10
Example 11
Example 12 Important
Example 13 Important
Example 14
Example 15 Important
Example 16 Important
Question 1
Question 2
Question 3 You are here
Question 4
Question 5 Important
Question 6 Important
Question 7 Important
Question 8
Question 9
Last updated at April 16, 2024 by Teachoo
Example 11 Find the equation of the line whose perpendicular distance from the origin is 4 units and the angle which the normal makes with positive direction of x-axis is 15 . We need to find equation of line Perpendicular distance of AB from origin is 4 units & angle which the normal makes with (+)ve direction of x-axis is 15 By Normal from Equation of line is x cos + y sin = p where, p = normal distance from the origin & = angle which makes by the normal with positive x-axis Here p = 4 & = 15 Putting values x cos + y sin = p x cos 15 + y sin 15 = 4 x (( 3 + 1)/(2 2)) + y (( 3 1)/(2 2)) = 4 ( ( 3 + 1) + ( 3 1))/(2 2) = 4 x( 3 + 1) + y( 3 1) = 4 2 2 ( 3 + 1)x + ( 3 1)y = 8 2 Which Is the required equation