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Example 6 - Chapter 9 Class 11 Straight Lines
Last updated at April 16, 2024 by Teachoo
Chapter 9 Class 11 Straight Lines
Concept wise
- Cordinate geometry questions
- Slope - Finding slope
- Slope - Prependicularity
- Angle between two lines by Slope
- Collinearity of 3 points by sliope
-
Point Slope form
- Slope-Intercept form
- Intercept form
- Normal form
- Given Statement
- Two lines // or/and prependicular
- Angle between two lines
- Distance - Between two parallel lines
- Distance of a point from a line
- Distance of a point from a line along a line
- Other Type of questions - Area of Triangle formed
- Other Type of questions - 3 lines Concurrent
- Other Type of questions - Image
- Other Type of questions - Mix
Transcript
Example 6 Write the equation of the line through the points (1, 1) and (3, 5). We know that equation of line through two points (x1, y1) & (x2, y2) is y y1 = (y2 y1)/(x2 x1) (x x1) Since equation of the line through the points (1, 1) and (3, 5). Here, x1 = 1, y1 = 1, & x2 = 3 and y2 = 5 Putting values (y (-1)) = (5 ( 1))/(3 1) (x 1) y + 1 = (5 + 1)/2 (x 1) y + 1 = 6/2 (x 1) y + 1 = 3(x 1) y + 1 = 3x 3 y 3x + 1 3 = 0 y 3x 2 = 0 Hence the required equation is y 3x 2 = 0
