Ex 9.3, 6 - Find distance between parallel lines 15x + 8y โ€“ 34 = 0 & - Ex 9.3

part 2 - Ex 9.3, 5 (i) - Ex 9.3 - Serial order wise - Chapter 9 Class 11 Straight Lines
part 3 - Ex 9.3, 5 (i) - Ex 9.3 - Serial order wise - Chapter 9 Class 11 Straight Lines

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Ex 9.3, 6 Find the distance between parallel lines 15x + 8y โ€“ 34 = 0 and 15x + 8y + 31 = 0 We know that , distance between two parallel lines Ax + By + C1 = 0 & Ax + By + C2 = 0 is d = |๐ถ_1โˆ’ ๐ถ_2 |/โˆš(๐ด^2 + ๐ต^2 ) Equation of first line is 15x + 8y โ€“ 34 = 0 Above equation is of the form Ax + By + C1 = 0 where A = 15, B = 8 & C1 = โˆ’ 34 Equation of second line is 15x + 8y + 31 = 0 Above equation is of the form Ax + By + C2 = 0 where A = 15 , B = 8 , C2 = 31 Distance between parallel lines 15x + 8y โ€“ 34 = 0 and 15x + 8y + 31 = 0 is d = |๐ถ_1โˆ’ ๐ถ_2 |/โˆš(๐ด^2 + ๐ต^2 ) Putting values d = |โˆ’34 โˆ’ 31|/โˆš(ใ€–(15)ใ€—^2 + (8)^2 ) d = |โˆ’34 โˆ’ 31|/โˆš(225 + 64) d = |โˆ’65|/โˆš289 d = 65/โˆš(17 ร— 17) d = 65/17 Thus, the required distance is ๐Ÿ”๐Ÿ“/๐Ÿ๐Ÿ• units

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