You are here
Ex 9.2, 15 - Chapter 9 Class 11 Straight Lines
Last updated at Dec. 16, 2024 by Teachoo
Chapter 9 Class 11 Straight Lines
Concept wise
- Cordinate geometry questions
- Slope - Finding slope
- Slope - Prependicularity
- Angle between two lines by Slope
- Collinearity of 3 points by sliope
- Point Slope form
- Slope-Intercept form
- Intercept form
- Normal form
-
Given Statement
- Two lines // or/and prependicular
- Angle between two lines
- Distance - Between two parallel lines
- Distance of a point from a line
- Distance of a point from a line along a line
- Other Type of questions - Area of Triangle formed
- Other Type of questions - 3 lines Concurrent
- Other Type of questions - Image
- Other Type of questions - Mix
Transcript
Ex 9.2, 15 The length L (in centimetre) of a copper rod is a linear function of its Celsius temperature C. In an experiment, if L = 124.942 when C = 20 and L = 125.134 when C = 110, express L in terms of C. Assuming C is along x-axis & L is along y-axis (x, y) = (C, L) So, we are given two points (20, 124.942) and (110, 125.134) So, from two point form y − y1 =(𝑦_2 − 𝑦_1)/(𝑥_2 − 𝑥_1 ) (x − x1) L − 124.942 = (125.134 − 124.942)/(110 − 20) (C − 20) L − 124.942 = (125.134 − 124.942)/(110 − 20) (C − 20) L − 124.942 = 0.192/90 (C − 20) L = (𝟎.𝟏𝟗𝟐)/𝟗𝟎 (C − 20) + 124.942
