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Ex 9.2, 13 Find equation of the line passing through the point (2, 2) and cutting off intercepts on the axes whose sum is 9. Equation of the line in intercept form is / + / = 1 where a = x - intercept & b = y-intercept Given that sum of intercepts is 9 a + b = 9 b = 9 a Putting value b = 9 a in equation / + /(9 ) = 1 Since point A(2, 2) lies on the line, it will satisfy the equation of line Putting x = 2 & y = 2 in the equation 2/ + 2/(9 ) = 1 ((9 a)2 + 2a)/(a(9 a)) = 1 18 2a + 2a = a(9 a) 18 0 = 9a a2 18 = 9a a2 a2 9a + 18 = 0 a2 6a 3a + 18 = 0 a(a 6) 3(a 6)= 0 (a 3) (a 6) = 0 So, a = 3 & a = 6

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo