Misc 12 - Chapter 8 Class 11 Sequences and Series
Last updated at Dec. 16, 2024 by Teachoo
Miscellaneous
Misc 2
Misc 3
Misc 4 Important
Misc 5
Misc 6
Misc 7 Important
Misc 8
Misc 9
Misc 10 Important
Misc 11 (i) Important
Misc 11 (ii)
Misc 12 Important You are here
Misc 13
Misc 14 Important
Misc 15 Important
Misc 16
Misc 17 Important
Misc 18 Important
Question 1
Question 2
Question 3 Important
Question 4
Question 5
Question 6 Important
Question 7
Question 8
Question 9 Important
Question 10
Question 11 Important
Question 12
Question 13 Important
Question 14
Miscellaneous
Last updated at Dec. 16, 2024 by Teachoo
Misc 12 Find the 20th term of the series 2 × 4 + 4 × 6 + 6 × 8 + … + n terms. Now, an = [nth term of 2, 4, 6 …] × [nth term of 4, 6, 8 …] = (2n) (2n + 2) = (2n) (2(n + 1)) = 4n (n + 1) Thus, nth term of series 2 × 4 + 4 × 6 + 6 × 8… is an = 4n (n + 1) We need to find 20th term of given series Putting n = 20 a20 = 4 × 2(20 + 1) = 80 (21) = 1680 Hence 20th term of series is 1680