Example 13 - Chapter 8 Class 11 Sequences and Series

Last updated at April 16, 2024 by

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Example 13 If A.M. and G.M. of two positive numbers a and b are 10 and 8, respectively, find the numbers. Now we have a + b = 20 (1) ab = 64 (2) From (2) ab = 64 a = 64/ Putting a = 64/ in (1) a + b = 20 64/ + b = 20 (64 + 2)/ = 20 64 + b2 = 20b b2 20b + 64 = 0 b(b 16) 4(b 16) = 0 (b 4)(b 16) = 0 b 4 = 0 or b 16 = 0 b = 4 or b = 16 Hence the numbers are a = 4, b = 16 or b = 4, a = 16

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo