Question 5 - Examples - Chapter 8 Class 11 Sequences and Series

Last updated at Dec. 16, 2024 by

Example 8 - Insert 6 number between 3 and 24 such that AP - Inserting AP between two numbers

Example 8 - Chapter 9 Class 11 Sequences and Series - Part 2

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Question 5 Insert 6 number between 3 and 24 such that the resulting sequence is an AP We know that to insert n number between a and b common difference = d = (𝑏 − 𝑎)/(𝑛 + 1) Here, We need to insert 6 numbers between 3 and 24 So, b = 24 , a = 3 & number of terms to be inserted = n = 6 Therefore, d = (24 − 3 )/(6 + 1) = 21/7 = 3 a = 3, d = 3 & b = 24 Hence six numbers between 3 and 24 are 6, 9, 12, 15, 13 & 21.

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo