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Question 5 - Inserting AP between two numbers - Chapter 8 Class 11 Sequences and Series
Last updated at Dec. 16, 2024 by Teachoo
Inserting AP between two numbers
Chapter 8 Class 11 Sequences and Series
Concept wise
- Finding Sequences
- Arithmetic Progression (AP): Formulae based
- Arithmetic Progression (AP): Statement
- Arithmetic Progression (AP): Calculation based/Proofs
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Inserting AP between two numbers
- Arithmetic Mean (AM)
- Geometric Progression(GP): Formulae based
- Geometric Progression(GP): Statement
- Geometric Progression(GP): Calculation based/Proofs
- Inserting GP between two numbers
- Geometric Mean (GM)
- AM and GM (Arithmetic Mean And Geometric mean)
- AP and GP mix questions
- Finding sum from series
- Finding sum from nth number
Transcript
Question 5 Insert 6 number between 3 and 24 such that the resulting sequence is an AP We know that to insert n number between a and b common difference = d = (𝑏 − 𝑎)/(𝑛 + 1) Here, We need to insert 6 numbers between 3 and 24 So, b = 24 , a = 3 & number of terms to be inserted = n = 6 Therefore, d = (24 − 3 )/(6 + 1) = 21/7 = 3 a = 3, d = 3 & b = 24 Hence six numbers between 3 and 24 are 6, 9, 12, 15, 13 & 21.
