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Ex9.1 , 14 The Fibonacci sequence is defined by 1 = a1 = a2 and an = an–1+an–2,n > 2 . Find π‘Ž_(𝑛+1)/an, for n = 1,2,3,4,5, Lets first calculate a1 , a2 , a3 , a4 , a5 & a6 It is given that a1 = 1 a2 = 1 For a3 , a4 , a5 & a6 we need to use an = an–1 + an–2 , n > 2 an = an-1 + an-2 , n > 2 Putting n = 3 in (1) a3 = a3 – 1 + a3 – 2 = a2 + a1 = 1 + 1 = 2 Putting n = 4 in (1) a4 = a4 – 1 + a4 – 2 a4 = a3 + a2 = 2 + 1 = 3 an = an-1 + an-2 , n > 2 Putting n = 5 in (1) a5 = a5 – 1 + a5 – 2 a5 = a4 + a3 = 3 + 2 = 5 Putting n = 6 in (1) a6 = a6 – 1 + a6 – 2 a6 = a5 + a4 = 5 + 3 = 8 Now, a1 = 1 , a2 = 1, a3 = 2 , a4 = 3 , a5 = 5 , a6 = 8

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo