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Question 14 What is the general solution of the differential equation 𝑒^(𝑦^β€² )=π‘₯ ? (A) 𝑦=π‘₯logπ‘₯+𝑐 (B) 𝑦=π‘₯logπ‘₯βˆ’π‘₯+𝑐 (C) 𝑦=π‘₯logπ‘₯+π‘₯+𝑐 (D) 𝑦=π‘₯+𝑐Given differential equation 𝑒^(𝑦^β€² )=π‘₯ Taking log both sides log(𝑒^(𝑦^β€² ))=log⁑π‘₯ 𝑦^β€² Γ— log e=log⁑π‘₯ Since log e = 1 𝑦^β€²=π‘™π‘œπ‘”β‘π‘₯ 𝑑𝑦/𝑑π‘₯ =π‘™π‘œπ‘”β‘π‘₯ 𝑑𝑦/𝑑π‘₯ =π‘™π‘œπ‘”β‘π‘₯ 𝑑𝑦=π‘™π‘œπ‘”β‘π‘₯ 𝑑π‘₯ Integrating both sides ∫1▒𝑑𝑦=∫1β–’γ€–π‘™π‘œπ‘”β‘π‘₯ 𝑑π‘₯γ€— π’š=∫1β–’γ€–π’π’π’ˆβ‘π’™ 𝒅𝒙〗 Putting ∫1β–’γ€–π‘™π‘œπ‘”β‘π‘₯ 𝑑π‘₯γ€—=π‘₯ log⁑π‘₯βˆ’π‘₯+𝐢 π’š=𝒙 π’π’π’ˆβ‘π’™βˆ’π’™+π‘ͺ So, the correct answer is (B)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo