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Ex9.1 , 11 Write the first five terms of the following sequence and obtain the corresponding series: a1 = 3,an = 3an – 1 + 2 for all n >1 It is Given that a1 = 3 For a2 onwards, we have to use formula an = 3an – 1 + 2 Putting n = 2 in (1) a2 = 3a2-1 + 2 = 3a1 + 2 = 3 × 3 +2 = 9 + 2 = 11 Putting n = 3 in (1) a3= 3a3 – 1 +2 a3= 3a2 + 2 = 3 × 11 +2 = 33 + 2 = 35 Putting n = 4 in (1) a4= 3a4 – 1 +2 a4= 3a3 +2 = 3 × 35 +2 = 105 + 2 = 107 Putting n = 5 in (1) a5 = 3a5 – 1 +2 a5 = 3a4 +2 = 3 × 107 +2 = 321 + 2 = 323 Hence, first five terms are 3, 11, 35, 107, and 323. The corresponding series is 3 + 11 + 35 + 107 + 323 + …

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo