This question is similar Chapter 4 Class 12 Determinants - Ex 4.2

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https://www.teachoo.com/3229/690/Ex-4.3--2---Show-that-A-(a---b---c)--B-(b-c---a)--C-(c-a---b)/category/Ex-4.3/

 

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Question 6 If the points (𝑥_1,𝑦_1 ),(𝑥_2,𝑦_2 ) and (𝑥_1+𝑥_2,𝑦_1+𝑦_2 ) are collinear, then 𝑥_1 𝑦_2 is equal to (A) 𝑥_2 𝑦_1 (B) 𝑥_1 𝑦_1 (C) 𝑥_2 𝑦_2 (D) 𝑥_1 𝑥_2Three point are collinear if they lie on some line 𝑖.𝑒. They do not form a triangle ∴ Area of triangle = 0 We know that Area of triangle is given by ∆ = 1/2 |■8(x1&y1&1@x2&y2&1@x3&y3&1)| Here, x1 = x1, y1 = y1 x2 = x2, y2 = y2, x3 = x1 + x2, y3 = y1 + y2 Putting values ∆ = 1/2 |■8(𝑥_1&𝑦_1&1@𝑥_2&𝑦_2&1@𝑥_1+𝑥_2&𝑦_1+𝑦_2&1)| ∆ = 1/2[𝑥_1 (𝑦_2 × 1−(𝑦_1+𝑦_2 )× 1) − 𝑦_1 (𝑥_2 ×1 −(𝑥_1+𝑥_2 )×1) +1(𝑥_2 ×(𝑦_1+𝑦_2 )−(𝑥_1+𝑥_2 )×𝑦_2 ) ] ∆ = 1/2[𝑥_1 (𝑦_2 −𝑦_1−𝑦_2 ) − 𝑦_1 (𝑥_2 −𝑥_1−𝑥_2 ) + 1(𝑥_2 𝑦_1+𝑥_2 𝑦_2−𝑥_1 𝑦_2−𝑥_2 𝑦_2 ) ] ∆ = 1/2[−𝑥_1 𝑦_1+𝑥_1 𝑦_1+𝑥_2 𝑦_1−𝑥_1 𝑦_2] ∆ = 1/2[𝑥_2 𝑦_1−𝑥_1 𝑦_2] Putting Area of Triangle = ∆ = 0 0 = 1/2[𝑥_2 𝑦_1−𝑥_1 𝑦_2] 0 = 𝑥_2 𝑦_1−𝑥_1 𝑦_2 𝑥_1 𝑦_2=𝒙_𝟐 𝒚_𝟏 So, the correct answer is (A)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo