CBSE Class 10 Sample Paper for 2025 Boards - Maths Standard

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Question 35 (A) - CBSE Class 10 Sample Paper for 2025 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards

Last updated at Sept. 20, 2024 by

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Transcript

Question 35 (A) Find the mean and median of the following data: Let’s first find median Finding Median Median = l + (𝑁/2 βˆ’π‘π‘“)/𝑓 Γ— h Here, 𝑡/𝟐 ∴ 100 – 105 is the median class And, l = lower limit of median class h = class-interval cf = cumulative frequency of the class before median class f = frequency of the median class Putting values in formula Median = l + (𝑁/2 βˆ’π‘π‘“)/𝑓 Γ— h = 100 + (πŸ”πŸŽ βˆ’ πŸ“πŸ•)/πŸπŸ– Γ— 5 = 100 + 3/18 Γ— 5 = 100 + 5/6 = 100 + 0.83 = 100.83 Now, let’s find Mean Finding Mean Mean(π‘₯ Μ…) = a + h Γ— (βˆ‘β–’π’‡π’Šπ’–π’Š)/(βˆ‘β–’π’‡π’Š) Where a = assumed mean h = Class interval Also, βˆ‘β–’π’‡π’Š = 120 βˆ‘β–’π’‡π’Šπ’–π’Š = βˆ’39 Putting values in formula Mean(𝒙 Μ…) = a + h Γ— (βˆ‘β–’π’‡π’Šπ’–π’Š)/(βˆ‘β–’π’‡π’Š) π‘₯ Μ… = 102.5 + 5 Γ— (βˆ’39)/120 π‘₯ Μ… = 102.5 βˆ’ 39/24 = 102.5 βˆ’ 13/8 = 102.5 βˆ’ 1.625 𝒙 Μ… = 100.875 Therefore, Mean is 100.875

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.