This question is similar to Chapter 3 Class 10 Pair of Linear Equations in Two Variables - Ex 3.1

Please check the question here

https://www.teachoo.com/1512/499/Ex-3.2--7---Draw-graphs-of-x---y---1--0-and-3x---2y---12--0/category/Ex-3.2/

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Question 32 (A) Solve the following system of linear equations graphically: x+2y = 3, 2x-3y+8 = 0Our equations are x + 2y = 3 2x − 3y = −8 For Equation (1) x + 2y = 3 Putting x = 0 0 + 2y = 3 2y = 3 y = 3/2 y = 1.5 So, x = 0, y = 1.5 is a solution i.e. (0, 1.5) is a solution Putting y = 0 x + 2(0) = 3 x + 0 = 3 x = 3 So, x = 3, y = 0 is a solution i.e. (3, 0) is a solution For Equation (2) 2x − 3y = −8 Putting x = 0 2(0) − 3y = −8 −3y = −8 y = (−8)/(−3) y = 2.67 So, x = 0, y = 2.67 is a solution i.e. (0, 2.67) is a solution Putting y = 0 2x − 3(0) = −8 2x = −8 x = (−8)/2 x = −4 So, x = −4, y = 0 is a solution i.e. (−4, 0) is a solution We will plot both equations on the graph Since lines intersect at (−1, 2) ∴ x = −1, y = 2 is the solution of the pair of equations

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo