Question 23 - CBSE Class 10 Sample Paper for 2025 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards

Last updated at Sept. 17, 2024 by Teachoo

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Question 23 Evaluate: (2 sin^2⁡〖60°〗 − tan^2⁡〖30°〗)/sec^2⁡〖45°〗 (2 sin^2⁡〖60°〗 − tan^2⁡〖30°〗)/sec^2⁡〖45°〗 = (2(√3/2)^2 −(1/√3)^2)/(1/cos^2⁡〖45° 〗 ) = [𝟐(√𝟑/𝟐)^𝟐 −(𝟏/√𝟑)^𝟐 ] ×〖𝒄𝒐𝒔〗^𝟐⁡〖𝟒𝟓° 〗 = [2(√3/2)^2 −(1/√3)^2 ] ×(1/√2)^2 = [𝟐 ×𝟑/𝟒 −𝟏/𝟑] ×𝟏/𝟐 = [3/2 −1/3] ×1/2 = [(3 × 3 − 1 × 2)/(2 × 3)] ×1/2 = [(9 − 2)/6] ×1/2 = 7/6 ×1/2 = 𝟕/𝟏𝟐

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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