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Ex 8.1 , 6 Write the first five terms of the sequences whose nth term is an = n(n2 +5 )/4 We need to find the first five terms i.e. a1, a2, a3 , a4 and a5 Given an = n (( 2 + 5)/4) Putting n = 1 in (1) a1 = 1 ((12+ 5))/4 = 1 ((1 + 5))/4 = 6/4 = 3/2 Putting n = 2 in (1) a2 = 2 ((22 + 5))/4 = 2 ((4 + 5))/4 = 2 9/4 = 9/2 Putting n = 3 in (1) a3 = 3 ((32 + 5))/4 = 3 ((9 + 5))/4 = 3 14/4 = 21/2 Putting n = 4 in (1) a4 = 4 ((42 + 5))/4 = 4 ((16 + 5))/4 = 4 21/4 = 21 Putting n = 5 in (1) a5 = 5 ((52 + 5))/4 = 5 ((25 + 5))/4 = 5 30/4 = 75/2 Hence first five terms are 3/2 , 9/2 , 21/2 , 21 and 75/2 .

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo