This question is similar to CBSE Class 10 Sample Paper for 2021 Boards - Maths StandardPlease check the question here
CBSE Class 10 Sample Paper for 2025 Boards - Maths Standard
Question 2 You are here
Question 3 Important
Question 4 Important
Question 5 Important
Question 6
Question 7 Important
Question 8 Important
Question 9
Question 10 Important
Question 11 Important
Question 12
Question 13
Question 14
Question 15 Important
Question 16
Question 17
Question 18 Important
Question 19 Important
Question 20 Important
Question 21 (A)
Question 21 (B) Important
Question 22 (A) Important
Question 22 (B) Important
Question 23
Question 24 Important
Question 25
Question 26 (A) Important
Question 26 (B) Important
Question 27
Question 28 Important
Question 29 Important
Question 30 (A)
Question 30 (B) Important
Question 31
Question 32 (A) Important
Question 32 (B) Important
Question 33 - Part 1
Question 33 - Part 2 Important
Question 34 Important
Question 35 (A) Important
Question 35 (B)
Question 36 (i) - Case Based
Question 36 (ii) Important
Question 36 (iii) (A)
Question 36 (iii) (B) Important
Question 37 (i) - Case Based
Question 37 (ii)
Question 37 (iii) (A) Important
Question 37 (iii) (B) Important
Question 38 (i) - Case Based Important
Question 38 (ii)
Question 38 (iii) (A)
Question 38 (iii) (B) Important
CBSE Class 10 Sample Paper for 2025 Boards - Maths Standard
Last updated at Oct. 3, 2024 by Teachoo
This question is similar to CBSE Class 10 Sample Paper for 2021 Boards - Maths StandardPlease check the question here
Question 2 The value of k for which the system of equations 3π₯βππ¦=7 and 6π₯+10π¦=3 is inconsistent, is (A) β 10 (B) -5 (C) 5 (D) 7Since the system of equations is inconsistent It has no solution Finding ratios ππβππβπ=π Comparing with a1x + b1y + c1 = 0 β΄ a1 = 3 , b1 = βk , c1 = β7 ππ+πππβπ=π Comparing with a2x + b2y + c2 = 0 β΄ a2 = 6 , b2 = 10, c2 = β3 ππ/ππ π1/π2 = 3/6 π1/π2 = 1/2 ππ/ππ π1/π2 = (βπ)/10 ππ/ππ π1/π2 = (β7)/(β3) π1/π2 = 7/3 Since the equations donβt have a solution π1/π2 = π1/π2 β π1/π2 1/2=(βπ)/10β 7/3 Thus, 1/2=(βπ)/10 10/2=βπ 5 = βk β5 = k k = β5 So, the correct answer is (B)