Example 9 - Chapter 6 Class 11 Permutations and Combinations

Last updated at April 16, 2024 by

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Example 9 Find the number of permutations of the letters of the word ALLAHABAD. In ALLAHABAD There are 4A , 2L , 1H, 1B & 1D Since alphabets are repeating we will us this formula !/ 1! 2! 3! Total number of alphabets = 9 Here n = 9 , There are 4A s, 2L s hence taking p1 = 4 & p2 = 2 Hence total number of permutation = !/ 1! 2! = 9!/4!2! = (9 8 7 6 5 4!)/((2 1) 4!) = (9 8 7 6 5 )/2 = 7560

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo