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Misc 14 - Chapter 4 Class 11 Complex Numbers
Last updated at April 16, 2024 by Teachoo
Chapter 4 Class 11 Complex Numbers
Concept wise
- Quadaratic equation
- Two complex numbers equal
- Convert to a + ib form
- Identities (square, cube of 2 complex numbers)
- Division
- Power of i(odd and even)
- Conjugate
- Modulus,argument
- Polar representation
- Proof- Replacing iota with -iota
- Proof- Taking general complex numbers
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Proof- Solving
- Proof- Using modulus conjugate property (Pg 102)
Transcript
Misc, 20 If ((1 + )/(1 ))^ = 1, then find the least positive integral value of m. We need to find minimum value of m which is positive as well as integer. Lets first find the value of ((1 + )/(1 )) (1 + )/(1 ) Rationalizing = (1 + )/(1 ) (1 + )/(1 + ) = ((1 + ) (1 + ))/((1 )(1 + )) = (1 + )2/((1)2 ( )2) = (1 + ( )2 + 2 1 )/(1 2) = (1 + 2 + 2 )/(1 2) Putting i2 = 1 = (1+ ( 1) + 2 )/(1 ( 1) ) = (1 1+ 2 )/(1+1) = (0 + 2 )/2 = 2 /2 = Hence, (1 + )/(1 ) = Given ((1 + )/(1 ))^ = 1 ( ) = 1 We know that 2 = 1 Squaring both sides ( 2)2 = ( 1)2 4 = 1 Hence the minimum value of m which satisfies the equation is 4
