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Question 4 - Quadaratic equation - Chapter 4 Class 11 Complex Numbers
Last updated at April 16, 2024 by Teachoo
Chapter 4 Class 11 Complex Numbers
Concept wise
-
Quadaratic equation
- Two complex numbers equal
- Convert to a + ib form
- Identities (square, cube of 2 complex numbers)
- Division
- Power of i(odd and even)
- Conjugate
- Modulus,argument
- Polar representation
- Proof- Replacing iota with -iota
- Proof- Taking general complex numbers
- Proof- Solving
- Proof- Using modulus conjugate property (Pg 102)
Transcript
Misc 8 Solve the equation 27 2 10 + 1 = 0 27 2 10 + 1 = 0 The above equation is of the form 2 + + = 0 Where a = 27, b = 10, and c = 1 = ( ( ^2 4 ))/2 = ( ( 10 ) (( 10 )^2 4 ( 27 ) ( 1 )))/(2 27) = (10 (100 108))/(2 27) = (10 ( 8))/(2 27) = (10 ( 2 4 ))/(2 27) = (10 2 ( 2))/(2 27) = (2 (5 ( 2)))/(2 27) = (5 ( 2))/27 = (5 (2 1))/27 = (5 2 ( 1))/27 = (5 2 )/27 Thus, = (5 2 )/27
