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Ex5.1, 12 Find the multiplicative inverse of the Complex number √5 + 3𝑖 Multiplicative inverse of z = z – 1 Multiplicative inverse of z = 1/𝑧 Putting z = √5 + 3𝑖 multiplicative inverse of √5 + 3𝑖 = 1/(√5 + 3 𝑖) Rationalizing = 1/(√5 + 3𝑖) ×(√5 − 3𝑖)/(√5 − 3𝑖) = (√5 − 3𝑖)/(√5 + 3𝑖 )(√(5 )− 3𝑖) Using (a – b ) ( a + b ) = a 2 – b 2 = (√5 − 3𝑖)/((√5 )2− (3𝑖)2) "= " (√5 − 3𝑖)/(5 − 9𝑖2) Putting i 2 = −1 = (√5 − 3𝑖)/(5 − 9 (−1) ) = (√5 − 3𝑖)/(5 + 9 ) = (√5 − 3𝑖)/14 = (√5 )/14 − 3/14 𝑖

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo